NCERT Solutions
Board Paper Solutions
Ask & Answer
School Talk
Login
GET APP
Login
Create Account
Popular
Latest
Shubhrajyoti Ghosh
Subject: Maths
, asked on 19/3/18
No links please:
i) Prove that
∫
0
x
2
S
i
n
2
x
tan
-
1
sin
x
d
x
=
π
2
-
1
Answer
1
Jerin Sam
Subject: Maths
, asked on 19/3/18
Solve this:
Q.26. Evaluate :
∫
-
a
a
a
-
x
a
+
x
d
x
Answer
4
Ujjwal Sancheti
Subject: Maths
, asked on 19/3/18
Solve 33 no.
Q.33. Find
∫
0
π
4
d
x
cos
3
x
2
sin
2
x
.
Answer
2
Chaitanya Kapoor
Subject: Maths
, asked on 19/3/18
Integerate
Q.
∫
1
3
x
-
1
x
3
e
x
+
1
x
Answer
1
Jeneeta Eliza John
Subject: Maths
, asked on 19/3/18
Please solve
Q. Evaluate :
∫
x
2
-
1
x
x
4
+
3
x
2
+
1
d
x
Answer
1
Riya
Subject: Maths
, asked on 19/3/18
Question 69. Evaluate
∫
2
5
3
x
2
-
5
d
x
as a limit of a sum.
Answer
1
Riya
Subject: Maths
, asked on 19/3/18
Question 24. Evaluate
∫
1
4
x
-
1
+
x
-
2
+
x
-
4
d
x
Answer
1
Lavneesh Rajput
Subject: Maths
, asked on 19/3/18
Solve this:
Q.15. Find :
∫
3
x
+
1
4
-
3
x
-
2
x
2
d
x
Answer
1
Lavneesh Rajput
Subject: Maths
, asked on 19/3/18
Q
.
S
o
l
v
e
t
h
i
s
:
∫
0
π
4
x
sin
x
1
+
cos
2
x
d
x
Answer
1
Vidipta Fulpadia
Subject: Maths
, asked on 18/3/18
Integrate
∫
1
3
sin
2
x
+
8
cos
2
x
+
1
Answer
1
Ranjit Singh
Subject: Maths
, asked on 18/3/18
Q.25 second part
Q.25. Evaluate:
∫
π
4
π
2
cos
2
x
log
sin
x
d
x
Answer
1
Tithi
Subject: Maths
, asked on 18/3/18
Solve this:
Q.49.
∫
0
2
π
1
1
+
e
sin
x
d
x
Answer
2
Ujjwal Sancheti
Subject: Maths
, asked on 18/3/18
Solve this:
∫
d
x
sin
2
x
cos
4
x
Answer
3
Ranjit Singh
Subject: Maths
, asked on 18/3/18
Q.18
18
.
E
v
a
l
u
a
t
e
∫
x
2
-
1
d
x
x
4
-
3
x
2
+
1
Answer
1
Varnika Dhiman
Subject: Maths
, asked on 18/3/18
Kindly check if the given question is done correctly or not. [In book, it was done by directly using by-parts method, so lemme know if we can do this way or not.]
Q1
∫
x
sin
-
1
x
1
-
x
2
d
x
Answer
1
Prev
3
4
5
6
7
Next
What are you looking for?
i) Prove that
Q.26. Evaluate :
Q.33. Find
Q.
Q. Evaluate :
Q.15. Find :
Q.25. Evaluate:
Q.49.
Q1