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Indranil Nag
Subject: Maths
, asked on 11/1/18
Question no. 12
Answer
1
Yash
Subject: Maths
, asked on 8/1/18
Q. D is the mid point of side AB of triangle ABC and P is any point on BC. If CQ||PD meets AB in Q, prove that
ar(
∆
BPQ) = 1/2 ar(
∆
ABC)
Answer
1
Ayushi Kansara
Subject: Maths
, asked on 7/1/18
Q. In the adjoining figure, PQRS Is a parallelogram and line segment PA and RB bisects
∠
P and
∠
R respectively.Show that PA||RB.
Q.
∆
ABC and
∆
DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that:
i
.
∆
A
B
D
≅
∆
A
C
D
i
i
.
∆
A
B
P
≅
∆
A
C
P
i
i
i
.
A
P
b
i
s
e
c
t
s
∠
A
a
s
w
e
l
l
a
s
∠
D
Answer
2
Rayyan
Subject: Maths
, asked on 7/1/18
19. In Figure 6 Diagonals PR and QS of quadrilateral PQRS intersect each other at A. Show that
ar(
∆
PSA)
×
ar(
∆
QAR) = ar(
∆
PAQ)
×
ar(
∆
SAR).
20. Prove that equal chords of a circle subtend equal angles at the centre.
Answer
1
Aniket Bagaria Bagaria
Subject: Maths
, asked on 7/1/18
I want theanswer of Q.9.
Answer
3
Rishabh
Subject: Maths
, asked on 5/1/18
Q9
9.
D, E and F are respectively the mid-points of the sides BC, CA AND AB of a
△
A
B
C
.
Show that:
(i) BDEF is a parallelogram.
(ii) ar (DEF) = ar (ABC)
(iii) ar (BDEF) = ar (ABC)
Answer
1
Admya Maini
Subject: Maths
, asked on 5/1/18
If the area of a rhombus with side length '
x
' is
x
2
2
. What is the length of its longer diagonal?
(a)
2
x
(b)
3
x
(c)
2
+
2
x
(d)
2
+
3
x
Answer
2
Rishabh
Subject: Maths
, asked on 4/1/18
Q
18
.
I
n
f
i
g
.
A
P
|
|
B
Q
|
|
C
R
.
P
r
o
v
e
t
h
a
t
a
r
△
A
Q
C
=
a
r
P
B
R
Q
19
.
I
n
f
i
g
a
r
△
D
R
C
=
a
r
△
D
P
C
a
n
d
a
r
△
B
D
P
=
a
r
△
A
R
C
.
S
h
o
w
t
h
a
t
b
o
t
h
t
h
e
q
u
a
d
r
i
l
a
t
e
r
a
l
s
a
r
e
t
r
a
p
e
z
i
u
m
s
.
Answer
1
Rishabh
Subject: Maths
, asked on 4/1/18
Q
4
.
I
n
f
i
g
.
A
B
C
D
i
s
a
q
u
a
d
r
i
l
a
t
e
r
a
l
a
n
d
B
E
|
|
A
C
a
n
d
a
l
s
o
B
E
m
e
e
t
s
D
C
p
r
o
d
u
c
e
d
a
t
E
.
S
h
o
w
t
h
a
t
a
r
e
a
o
f
△
A
D
E
i
s
e
q
u
a
l
t
o
t
h
e
a
r
e
a
o
f
t
h
e
q
u
a
d
r
i
l
a
t
e
r
a
l
A
B
C
D
.
Q
5
.
D
i
a
g
o
n
a
l
s
A
C
a
n
d
B
D
o
f
a
t
r
a
p
e
z
i
u
m
A
B
C
D
w
i
t
h
A
B
|
|
D
C
i
n
t
e
r
s
e
c
t
e
a
c
h
o
t
h
e
r
a
t
O
.
P
r
o
v
e
t
h
a
t
a
r
△
A
O
D
=
a
r
△
B
O
C
Q
6
.
I
n
f
i
g
.
A
B
C
D
E
i
s
p
e
n
t
a
g
o
n
.
A
l
i
n
e
t
h
r
o
u
g
h
B
p
a
r
a
l
l
e
l
t
o
A
C
m
e
e
t
s
D
C
p
r
o
d
u
c
e
d
a
t
F
.
S
h
o
w
t
h
a
t
:
i
a
r
△
A
C
B
=
a
r
△
A
C
F
.
i
i
a
r
A
E
D
F
=
a
r
A
B
C
D
E
Answer
4
Rishabh
Subject: Maths
, asked on 4/1/18
Please solve questions from q8 to q14 . Fast !!!
Answer
1
Ravreet
Subject: Maths
, asked on 4/1/18
abcd is a parallelogram with x and y the mid points of side ab and cd respectively prove that the area of ar(axdy)=ar(bcyx)
Answer
1
Akhil Vashistha
Subject: Maths
, asked on 1/1/18
Q The base of a triangle ABC is divided at such that BE=1/2 EC.Prove that
a
r
(
△
A
B
E
)
=
1
3
a
r
(
△
A
B
C
)
Answer
3
Samriddhi Singh
Subject: Maths
, asked on 31/12/17
Me and my friends have to make a project for school exhibition and we're given maths as the subject . Can anyone please give me some ideas for the project?
Answer
1
Shravani Pandey
Subject: Maths
, asked on 31/12/17
How 1/4 ar(triangle DBC) =ar(triangle CYX)
Q. EXAMPLE 44
: ABCD is a parallelogram X and Y are the mid-point of BC and CD respectively. Prove that ar (
∆
AXY ) =
3
8
ar ( ||
gm
ABCD)
Answer
1
Scarlett
Subject: Maths
, asked on 29/12/17
ABCD is a parallelogram And X is the midpoint of AB If area of AXCDX is equals to 24 cm square find Area of ABC
Answer
1
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Next
What are you looking for?
Q. D is the mid point of side AB of triangle ABC and P is any point on BC. If CQ||PD meets AB in Q, prove that
ar(BPQ) = 1/2 ar(ABC)
Q. ABC and DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that:
ar(PSA) ar(QAR) = ar(PAQ) ar(SAR).
20. Prove that equal chords of a circle subtend equal angles at the centre.
9. D, E and F are respectively the mid-points of the sides BC, CA AND AB of a .
Show that:
(i) BDEF is a parallelogram.
(ii) ar (DEF) = ar (ABC)
(iii) ar (BDEF) = ar (ABC)
(a) (b) (c) (d)
Q. EXAMPLE 44 : ABCD is a parallelogram X and Y are the mid-point of BC and CD respectively. Prove that ar ( AXY ) = ar ( ||gm ABCD)