Subject: Maths, asked on 6/3/18
Subject: Maths, asked on 5/3/18

## Solve this: Q.17. Find the term containing ${x}^{10}$ in the expansion of ${\left(2{x}^{2}-3/x\right)}^{11}$                                                                   OR Find the term independent of x in the expansion of

Subject: Maths, asked on 1/3/18

## ​Using Binomial theorem prove that 6^n - 5n-1 is divisible by 25 for all n element of N

Subject: Maths, asked on 21/2/18

## .Find the coefficient of x ^32 and x ^−17 in the expansion of (x ^4 − 1/ x 3 ) ^15 .

Subject: Maths, asked on 8/2/18

## Solve this: ​Q3. Determine the value of x in the expression (x + xlog x)5 if the third term in the expansion is 10,00,000.

Subject: Maths, asked on 8/2/18

## Problem 3: If $p+q=1$, then show that $\sum _{r=0}^{n}{r}^{2}{C}_{r}{p}^{r}{q}^{n-r}=npq+{n}^{2}{p}^{2}$.

Subject: Maths, asked on 8/2/18

## If x + y = 1, then $\sum _{r=0}^{n}{r}^{n}{C}_{r}{x}^{r}{y}^{n-r}$  equals (A) 1                       (B) n                       (C) nx                    (D) ny

Subject: Maths, asked on 8/2/18

## Solve this: Q). Find the remainder when ${\left(106\right)}^{85}-{\left(85\right)}^{106}+1$ is divisible by 7.

Subject: Maths, asked on 7/2/18

## Find the coefficient of a4 in the product (1+2a)4 (2-a)5 using binomial theorem

Subject: Maths, asked on 31/1/18

## Solve this:

Subject: Maths, asked on 29/1/18

## Can you please explain this question by taking coff step by step.

Subject: Maths, asked on 21/1/18

## Solve this: Q9. The co-efficient of xk ($0\le \mathrm{k}\le \mathrm{n}$) in the expansion of E = 1 +(1+ x) + (1+x)2 +......+ (1 + x)n is          Q10. The last term in the binomial expansion of . Then the 5th term from the beginning is

Subject: Maths, asked on 8/1/18

## Q 12 please answer as soon as possible

Subject: Maths, asked on 4/1/18

## Solve (9X - 1/?3x)^18 by binomial theorem

Subject: Maths, asked on 31/12/17

## Q. If the coefficients of 5th , 6th and 7th terms of ${\left(1+x\right)}^{n}$ are in A.P., then n = 10 12 14 15

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