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Shreyas
Subject: Maths
, asked on 23/4/18
If the smaller one divides three times the larger of two numbers, we get 4 as quotient and 3 as the remainder. Also, if seven times the smaller number is divided by the larger one, we get 5 as quotient and 1 as remainder. Find the numbers.
*
i want the ansr for this only
Answer
1
Shreyas
Subject: Maths
, asked on 23/4/18
Solve:
^{𝑥 }
+
^{𝑦 }
= 2; ax-by=a
^{2}
– b
^{2}
𝑎 𝑏
3(2u + v) = 7uv; 3(u + 3v) = 11uv
55 + 40 = 13; 44 + 30 = 10
𝑥+𝑦 𝑥−𝑦 𝑥+𝑦 𝑥−𝑦
*
please do nt give substitute or any other references.
Answer
1
Akhilesh Kumar
Subject: Maths
, asked on 23/4/18
Solve this:
Answer
3
Siddharth
Subject: Maths
, asked on 21/4/18
Pls tell all the ans
Answer
1
Nikhil
Subject: Maths
, asked on 21/4/18
3. A boat goes 30 km upstream and 44 km downstream in 10 hours. In '13 hours it can go 40 km upstream and 55 km downstream. Determine the speed of the stream and that of the boat in still water.
4. x takes 3 hours more than y to walk 30 km. But if x doubles his pace, he is ahead of y by one and a half of hours. Find their speeds.
Answer
1
Shreya Bharti
Subject: Maths
, asked on 15/4/18
Solve by cross multiplication method....ans fast
Answer
3
Sahil.....
Subject: Maths
, asked on 14/4/18
1st question ?part....?????
Answer
2
Srishti Singh
Subject: Maths
, asked on 12/4/18
The digit in the tens place of a number consisting of two digits is greater than that in the units place by 7.The sum of digits 1/9th of the number.Find the number.
Answer
1
Junaki
Subject: Maths
, asked on 8/4/18
solve for:
37x+41y=70
41x+37y=86
Answer
1
Kamalika Bhowmik
Subject: Maths
, asked on 7/4/18
Q. I am not able to understand this part...please explain me fast
But we know :
${4}^{4}$
= 256 , So we can see that the same number 'x' we add into ' 27 ' and subtract from ' 55 ' will never gives 256 , So we neglect that combination .
Answer
1
Kamalika Bhowmik
Subject: Maths
, asked on 7/4/18
sir,can u please explain why the other cases will not be possible?
Answer
1
Shubham
Subject: Maths
, asked on 7/4/18
3 men and 4 women can do a work working together in 12 days whereas 9 men and 2
women can do the same work working together in 9 days. Find in how many days can 3
men and 2 women together do the same work?
Answer
1
Shubham
Subject: Maths
, asked on 7/4/18
Sum of the digits of a three digit number is 7 and the digit at ten’s place is unity. On
reversing the order of the digits, the new number obtained is 16 less than twice the
original number. Find the number.
Answer
1
Shubham
Subject: Maths
, asked on 7/4/18
Six years ago a father’s age was 2 years more than 8 times the son’s age that time. After
10 years from now father will be 2.5 times as old as the son that time. Find
(i) Their present ages
(ii) After how many years from today, will the age of father be twice the age
of his son that time?
Answer
2
Kamalika Bhowmik
Subject: Maths
, asked on 7/4/18
pls solve this question fast.solve for x
Q.
${\left(x+27\right)}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$4$}\right.}+{\left(55-x\right)}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$4$}\right.}=4$
Answer
1
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What are you looking for?

*

i want the ansr for this only- Solve:

𝑎 𝑏^{𝑥 }+^{𝑦 }= 2; ax-by=a^{2}– b^{2}- 3(2u + v) = 7uv; 3(u + 3v) = 11uv
- 55 + 40 = 13; 44 + 30 = 10

𝑥+𝑦 𝑥−𝑦 𝑥+𝑦 𝑥−𝑦*

please do nt give substitute or any other references.4. x takes 3 hours more than y to walk 30 km. But if x doubles his pace, he is ahead of y by one and a half of hours. Find their speeds.

37x+41y=70

41x+37y=86

But we know : ${4}^{4}$ = 256 , So we can see that the same number 'x' we add into ' 27 ' and subtract from ' 55 ' will never gives 256 , So we neglect that combination .

women can do the same work working together in 9 days. Find in how many days can 3

men and 2 women together do the same work?

Sum of the digits of a three digit number is 7 and the digit at ten’s place is unity. On

reversing the order of the digits, the new number obtained is 16 less than twice the

original number. Find the number.

10 years from now father will be 2.5 times as old as the son that time. Find

(i) Their present ages

(ii) After how many years from today, will the age of father be twice the age

of his son that time?

Q. ${\left(x+27\right)}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$4$}\right.}+{\left(55-x\right)}^{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$4$}\right.}=4$