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Gaurav
Subject: Maths
, asked on 21/5/18
In figure, angle ACB =90 ,CD perpendicular on AB, prove that CD 2=BD.AD
Answer
1
Neha
Subject: Maths
, asked on 17/5/18
Solve this:
Q.6. In the given figure DE
$\parallel $
BC, AD : DB = 1 : 2, find
$\frac{ar\u25b3ADE}{ar\u25b3ABC}$
Answer
2
Siddharth
Subject: Maths
, asked on 16/5/18
My one question has not been ans yet?
Answer
1
Siddharth
Subject: Maths
, asked on 16/5/18
How many theorem we have to learn in maths full syllabus
Answer
2
Neha
Subject: Maths
, asked on 16/5/18
Solve this:
Answer
1
Rimas Musa
Subject: Maths
, asked on 22/4/18
(8x -7x)(3x-1)= (4x -3)(5x-3)
Solve this..
Answer
1
Rimas Musa
Subject: Maths
, asked on 22/4/18
2x -(x-3)x-2 = 2x +3 -(x-2)x-3
How to solve?
Answer
2
Aaradhya Verma
Subject: Maths
, asked on 20/4/18
Q. ABC is a equilateral triangle in which AO=BO=CO=r. Find the length of r.
Answer
1
Himanshu Sharma
Subject: Maths
, asked on 6/4/18
ABC is an Triangle and D is perpendicular on BC ab = p BC equals to q prove that a + b into a minus b equals to C + D *intoC minus d
Answer
2
Abhishek Gupta
Subject: Maths
, asked on 3/4/18
135.
$1-\mathrm{log}5=\frac{1}{3}\left(\mathrm{log}\frac{1}{2}+\mathrm{log}x+\frac{1}{3}\mathrm{log}5\right).$
Answer
2
Dishank Agrawal
Subject: Maths
, asked on 2/4/18
what are the important questions of chapter 6 triangles ?
Answer
1
R.k. Rearden
Subject: Maths
, asked on 2/4/18
Prove that in any triangle the sum of the squares of any two sides is equal to twice the square of half of the third side together with twice the square of the median, which bisects the third side.
Answer
2
Naina
Subject: Maths
, asked on 1/4/18
Solve this:
Answer
1
Son Ser
Subject: Maths
, asked on 30/3/18
Plzz fast i have exams
Answer
2
Ayan
Subject: Maths
, asked on 30/3/18
Solve this :
$6.\mathrm{Out}\mathrm{of}200\mathrm{bulbs}\mathrm{in}\mathrm{a}\mathrm{box},12\mathrm{bulbs}\mathrm{are}\mathrm{defective}.\mathrm{One}\mathrm{bulb}\mathrm{is}\mathrm{taken}\mathrm{out}\mathrm{at}\mathrm{random}\mathrm{from}\mathrm{is}\mathrm{the}\mathrm{probability}\mathrm{that}\mathrm{the}\mathrm{drawn}\mathrm{bulb}\mathrm{is}\mathrm{not}\mathrm{defective}?\phantom{\rule{0ex}{0ex}}7.\mathrm{Find}\mathrm{the}\mathrm{HCF}\mathrm{LCM}\mathrm{of}90\mathrm{and}144\mathrm{by}\mathrm{the}\mathrm{method}\mathrm{of}\mathrm{prime}\mathrm{factorization}.$
Answer
3
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Q.6. In the given figure DE$\parallel $BC, AD : DB = 1 : 2, find $\frac{ar\u25b3ADE}{ar\u25b3ABC}$

Solve this..

How to solve?

Solve this :$6.\mathrm{Out}\mathrm{of}200\mathrm{bulbs}\mathrm{in}\mathrm{a}\mathrm{box},12\mathrm{bulbs}\mathrm{are}\mathrm{defective}.\mathrm{One}\mathrm{bulb}\mathrm{is}\mathrm{taken}\mathrm{out}\mathrm{at}\mathrm{random}\mathrm{from}\mathrm{is}\mathrm{the}\mathrm{probability}\mathrm{that}\mathrm{the}\mathrm{drawn}\mathrm{bulb}\mathrm{is}\mathrm{not}\mathrm{defective}?\phantom{\rule{0ex}{0ex}}7.\mathrm{Find}\mathrm{the}\mathrm{HCF}\mathrm{LCM}\mathrm{of}90\mathrm{and}144\mathrm{by}\mathrm{the}\mathrm{method}\mathrm{of}\mathrm{prime}\mathrm{factorization}.$