Factorise: 16x^{5} - 144x^{3}

please factorize :

a4+3a2+4

if x = 3^{1/3 }+ 3 ^{-1/3}, then^{}whatis the value of 3x^{3} - 9x ?

a) 12 b) 9 c)15 d) 10 how??

Factorise

(i) a^{4} − b^{4}

(ii) p^{4} − 81

(iii) x^{4} − (y + z)^{4}

(iv) x^{4} − (x − z)^{4}

(v) a^{4} − 2a^{2}b^{2} + b^{4}

If x-y=12 and xy=25/4,find x+y

factorize the following equation:

(x-2y)^{2}+4x-8y

solve:-

44(x^{4} - 5x^{3} -24x^{2)} divided by 11x(x-8)

Factorise the expression as directed:

(5p2 - 25p + 20) :(p - 1)

(i) 4p^{2 }− 9q^{2}

(ii) 63a^{2} − 112b^{2}

(iii) 49x^{2} − 36

(iv) 16x^{5} − 144x^{3}

(v) (l + m)^{2} − (l − m)^{2}

(vi) 9x^{2}y^{2} − 16

(vii) (x^{2} − 2xy + y^{2}) − z^{2}

(viii) 25a^{2} − 4b^{2 }+ 28bc − 49c^{2}

12(2x-3y)^2-16(3y-2x)

Factorise:-

x^{2}+22x-48

factorize:

x(a-3)+y(3-a)

facotorise (2x-3)^{2} -8x +12

Factorise the expression q^{2} - 10q + 21

12pq(9p^2-16q^2) divided by 4pq(3p+4q)

Factorise 6xy - 4y + 6 -9x by regrouping method. Please explain the regrouping of 6-9x to get the common factor 3x-2 as it is the same obtained in the 6xy -4y

x^{2}-2xy+y^{2}-a^{2}-2ab-b^{2}

factorise it

Factorise: 16x

^{5}- 144x^{3}^{2}-6ax+(a^{2}-b^{2}).x

^{2}-y^{2}-2yz-z^{2}please factorize :

a4+3a2+4

if x = 3

rn^{1/3 }+ 3^{-1/3}, then^{}whatis the value of 3x^{3}- 9x ?a) 12 b) 9 c)15 d) 10 how??

Factorise

(i)

a^{4}−b^{4}(ii)

p^{4}− 81(iii)

x^{4}− (y+z)^{4}(iv)

x^{4}− (x−z)^{4}(v)

a^{4}− 2a^{2}b^{2}+b^{4}factorise and then divide 24x²-65xy+21y²/8x-3y

If x-y=12 and xy=25/4,find x+y

Pls solve fast.

factorize the following equation:

(x-2y)

^{2}+4x-8ysolve:-

44(x

^{4}- 5x^{3}-24x^{2)}divided by 11x(x-8)^{2}- (y-z)^{2}/(x+z)^{2 }-y^{2) }+ (y^{2 }- (x-z)^{2}/ (x+z)^{2}- z^{2}) + (z^{2}- (x-y)^{2}/ (y+z)^{2 }- x^{2})Factorise the expression as directed:

(5p2 - 25p + 20)

~~:~~(p - 1)3x

^{2}+10x+8^{2 }+ 1/x^{2}= 34 , find the value of x + 1/x.In a polynomial, the exponents of all the variables must be :a) whole numbers

b) natural numbers

c) rational numbers

d) integers

Your earlyresponse will behighly appreciated .....

Factorise

(i) 4

p^{2 }− 9q^{2}(ii) 63

a^{2}− 112b^{2}(iii) 49

x^{2}− 36(iv) 16

x^{5}− 144x^{3}(v) (

l+m)^{2}− (l−m)^{2}(vi) 9

x^{2}y^{2}− 16(vii) (

x^{2}− 2xy+y^{2}) −z^{2}(viii) 25

a^{2}− 4b^{2 }+ 28bc− 49c^{2}12(2x-3y)^2-16(3y-2x)

Factorise:-

x

^{2}+22x-48factorize:

x(a-3)+y(3-a)

facotorise

(2x-3)^{2}-8x +12Factorise the expression q^{2}- 10q + 2112pq(9p^2-16q^2) divided by 4pq(3p+4q)

Factorise 6xy - 4y + 6 -9x by regrouping method. Please explain the regrouping of 6-9x to get the common factor 3x-2 as it is the same obtained in the 6xy -4y

x

^{2}-2xy+y^{2}-a^{2}-2ab-b^{2}factorise it