0 4 (x-3) = 0 05 (y+2) 0 2 (x+y) = 0 1 (6y+8) Solve the pair of equation by - Maths - Pair of Linear Equations in Two Variables

Question

0 4 (x-3) = 0 05 (y+2)
0 2 (x+y) = 0 1 (6y+8)
Solve the pair of equation by cross multiplication method

Ashwini Kumar · Accepted Answer

We have,0 4x-3=0
05y+2⇒8x-3=y+2    Multiplying both sides by 20⇒8x-24=y+2⇒8x-y=26     
1And0 2x+y=0
16y+8⇒2x+y=6y+8      Multiplying both sides by 10⇒2x+2y=6y+8⇒2x-4y=8     
2From 1-2×4, we get   8x-   y=26   8x-16y=32     0   +15y=-6⇒y=-615=-25=-0
4putting y=-0 4 in 1, we get8x+0
4=26⇒8x=25 6⇒x=25 68=3 2Hence, x=3
2 and y=-0 4

0.4 (x-3) = 0.05 (y+2) 0.2 (x+y) = 0.1 (6y+8) Solve the pair of equation by cross multiplication method

0.4 (x-3) = 0.05 (y+2)
0.2 (x+y) = 0.1 (6y+8)
Solve the pair of equation by cross multiplication method