0 5 mole of calcium carbonate is decomposed by an aqueous solution containing 25% HCl by mass Calculatethe mass - Chemistry - Solutions

Question

0 5 mole of calcium carbonate is decomposed
by an aqueous solution containing 25% HCl by mass Calculatethe mass
of the solution consumed

Priya G N · Accepted Answer

The chemical reaction is:

CaCO3 + 2HCl ---------> CaCl2 + H2O + CO2

The above equation shows that to decompose 1 mole of CaCO3, we need
2 moles of HCl Therefore, 0 5 mole of CaCO3 requires 0 5x2 = 1 mole
of HCl

We know that 1 mole of HCl = 36 5 g

It is given an aqueous solution containing 25% HCl by mass which
means 100 g of solution contains 25 g of HCl Therefore in order to
have 36 5 g of HCl, we need

= (36 5x100)/25

= 146 g of solution
Hence 146 g
of solution is consumed

0.5 mole of calcium carbonate is decomposed by an aqueous solution containing 25% HCl by mass. Calculatethe mass of the solution consumed.