1. A particle is projected from ground in vertical direction at t = 0. At t = 0.8s, it reaches h = 14 m. It will again come to same height at t = 

• 2s
• 14/5 s
• 3s
• 7/2 s

2. In the figure shown, the blocks A and C are pulled down with constant velocities u. Acceleration of block B is 

$$\begin{gathered} a. \frac{u^2}{b}{\tan }^2\theta se{c}^2\theta \\ b. \frac{u^2}{b}{\tan }^3\theta \\ c. \frac{u^2}{b}\tan \theta se{c}^2\theta \\ d. zero \end{gathered}$$