1. A stone is dropped from rest and falls freely under the gravity . Calculate the disctance covered by it in the first two seconds (G=10m/s2)

2. A body initially at rest ravels a distance 100 m in 5s with a constant acceleration. Calculate (1) the acceleration (2) final velocity at the end of 5s.

3, Follwing fig show v-t graph for a body in motion. Use it to find the displacement of a body at t=4s

Unable to draw the diagram on this sheet

1· Distance covered by a stone freely falling from rest after 2 seconds is given by
s=ut + 0·5at​2
Here initial velocity u = 0
= acceleration due to gravity = 10m/s2
time t= 2s
=( 0×2) + (0·× 10 × 4) = 20m


2. To calculate acceleration, we need 
s=ut + 0·5at​2
Here s=100m
​u=0
t=5s

​100 = ( 0×5) + (0·××25)
100 = 25a/2
= 8m/s2

To calculate final velocity, we need to put values in v=u+at

v= 0 + 8×= 40m/s
 

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pls answer the quest at the earliest. Need very urgently.

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