1. calculate the ratio of atoms present in 4g of magnesium and 4g of iron. (Mg = 24, Fe = 56 ) 2. what is th mass in grams of each of the following ? (a) 1.0 mole of Cu (b) 0.5 mole of S (c) 6.022 x 10^23 atoms of Ca 3. calculate the weight of one atom of hydrogen.
1) Molar mass of magnesium = 24 g
Molar mass of iron = 56 g
24 g of magnesium contains = 6.0221023 atoms
4 g of magnesium =
56 g of iron contains = 6.0221023 atoms
4 g of iron =
Ratio of 4 g of Mg and 4 g of Fe = 7 : 3
2) a) Number of moles (n) =
1 mole of Cu =
Mass of Copper = 163.5 = 63.5 g
b) 0.5 mole of S
0.5 =
Mass of S = 0.532 = 16 g
c) n =
n = = 1 mole
1 =
Given mass = = 40 g
3) 6.0221023 atoms of hydrogen weighs = 1 g
1 atom of hydrogen weighs = = 0.16610-23 g
Molar mass of iron = 56 g
24 g of magnesium contains = 6.0221023 atoms
4 g of magnesium =
56 g of iron contains = 6.0221023 atoms
4 g of iron =
Ratio of 4 g of Mg and 4 g of Fe = 7 : 3
2) a) Number of moles (n) =
1 mole of Cu =
Mass of Copper = 163.5 = 63.5 g
b) 0.5 mole of S
0.5 =
Mass of S = 0.532 = 16 g
c) n =
n = = 1 mole
1 =
Given mass = = 40 g
3) 6.0221023 atoms of hydrogen weighs = 1 g
1 atom of hydrogen weighs = = 0.16610-23 g