1) if x=1, y=2 and z=3, find the value of 
2) simplify : 3(x+6)+2(x+3)=64. check the result.
3)simplify : (a-8ab- 5)+ (3ab-4a2+8)

Dear Student,

23x+6+x+3=643x+18+x+3=64x+21=644x=64-214x=43x=434Now,L.H.S.=3x+6+x+3           =3434+6+434+3           =3×43+244+43+124           =3×674+554           =201+554           =2564           =64           =R.H.SHence Verified

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2) 3(1+6)+2(1+3)=64
= 3*7+2*4
= 21+8= 29
so 29 is not equal to 64

3) As we know that when we remove bracket the sign inside it changes
so it will be a2+8ab+5-3ab+4a2 - 8
= 5a + 5ab - 3
 
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