1 into 1! + 2 into 2 ! + 3 into 3!+ ... + 10 into n factorial=(n+1)!-1. prove this
Dear Student,
First we prove it's true for n=1 1(1!) = 1(1) = 1 and (1+1)!-1 = 2!-1 = 2-1 = 1 Now we assume it's true for n=k (1) 1(1!)+2(2!)+3(3!)+...+k(k!) = (k+1)!-1 We need to show that (2) 1(1!)+2(2!)+3(3!)+...+(k+1)(k+1)! ≟ (k+2)!-1 We add (k+1)(k+1)! to both sides of (1) (1) 1(1!)+2(2!)+3(3!)+...+k(k!)+(k+1)(k+1)! = (k+1)!-1+(k+1)(k+1)! = = (k+1)!+(k+1)(k+1)!-1 = = (k+1)![1+(k+1)]-1 = = (k+1)![1+k+1]-1 = = (k+1)!(k+2)-1 = = (k+2)!-1 So the truth of (1) implies the truth of (2). So the induction is complete. Regards