1. name the type of triangle pqr formed by the points p(√2,√2) , q(-√2,-√2) and r(-√6,√6)
2. abcd is a parallelogram with vertices a(x1,y1) b(
x2,y2) and c(x3,y3). find the coordinated of the fourth vertex d in terms of x1,x2,x3,y1,y2,y3
we were assigned 30 sums as homework.. i dint know how to solve these two out of them. please help me out....
Let Δ PQR be the given triangle.
Applying the distance formulae, we get
Since, PQ = QR = RP = 4
∴ ∆PQR is an equilateral triangle.
(2)
Given, ABCD is a parallelogram.
Let the coordinates of the vertex D be (x4, y4).
We know that, diagonals of a parallelogram bisect each other.
∴ Coordinate of mid point of diagonal BD = Coordinate of mid point of diagonal AC
Coordinate of mid point of diagonal
Coordinate of mid point of diagonal
Thus, coordinates of the fourth vertex D are (x1 + x3 – x2, y1 + y3 – y2)