1) Prove that sum of any two sides of a triangle is greater than twice the median with respect to third side.

2) Show that the sum of three altitudes of a triangle is less than the sum of all three sides of triangle.

3) Prove that any two sides of a triangle are together greater than twice the median drawn to the 3rd side.

4) Prove that the perimeter of a triangle is greater than the sum of its medians.

5) In a quadrilateral ABCD in which diagonals AC BD intersects at O. Show that AB+BC+CD+DA 2(AC+BD)

6) ABC is a triangle in which angle B = twice angle C. D is a point on side BC such that AD bisects angle A and AB= CD. Prove that Angle BAC=72

The answer provided above by sahil sharma is correct . In case you need any extra help or need extra explanation you can get back to us.

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