{1/sec2q - cos2q + 1/cosec2q - sin2q} (sin2q cos2q) = 1- sin2q cos2q/2+ sin2q cos2q - Maths - Some Applications of Trigonometry

Question

{ 1/sec2 q
- cos2 q +
1/cosec2 q -
sin2 q }
(sin2 q
cos2 q ) =
1- sin2 q
cos2 q /2+
sin2 q cos2
q

Aneesa Attaullah · Answer

I seriously hate this chapter, i have it fr my exam but god
knows how i m gonna study this its damm confusing ~!!!

{ 1/sec2 q - cos2 q + 1/cosec2 q - sin2 q } (sin2 q cos2 q ) = 1- sin2 q cos2 q /2+ sin2 q cos2 q