1)- What is the pH of10-8 (N) HCl?

The pH of 10-8 N HCl can be calculated as follow:

[H+] = 10-8 N

As the solution is so dilute that water will also dissociate to produce H+ ions 

H2O → H+ + OH-

Now, 

The Concentration of H+ released from water is 10-7 as the pH of water is equal to 7.

Hence the total concentration of H+ = 10-7 + 10-8 

[H+] = 10-7 + 0.1 × 10-7 

= 1.1 × 10-7 

pH = -log [H+]

Hence pH = 6.95 

Hence the pH of 10-8 N solution of HCl = 6.95. 

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