10 MOLES N2 AND 15 MOLES H2 WERE ALLOWED TO REACT OVER A SUITABLE CATALYST .10 MOLES OF NH3 WERE FORMED .THE REMAINING MOLES OF N2 AND H2 RESPECTIVELY ARE:1) 5 MOLES ,0 MOLES (2) 0 MOLES,5 MOLES3) 9 MOLES,12 MOLES (4)0 MOLES, 0 MOLESSIR / MADAM,COULD YOU PLEASE SOLVE THE ENTIRE SUM,SO THAT I GET TO KNOW HOW IT IS SOLVED,AND THEN CHOOSE THE CORRECT OPTION.

Reaction of N2 and H2 to form NH3 is given as,
N2 + 3H2 $\to$ 2NH3
According to the equation, 1 mole of N2 requires 3moles of H2 to form 2 moles of NH3.
Ratio- N2 : H2 : NH3  = 1 : 3 : 2

Now we have 10 moles of N2 for which we require 3$×$10 = 30 moles of H2  to react completely. But we have only 15 moles of H2 that means H2  is the limiting reactant.
Therefore, 15 moles of H2​ will react only with 5 moles of N2 to form 10 moles of NH3.

So correct option is 1) 5 moles of N2 will remain and 0 moles of H2 will remain.

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