12 gram of urea is dissolved in 2 litre solution at 300K temperatures how many grams of NaCl should be dissolved in 10 litre solution so that it becomes iso-osmotic with urea solution? a. 7.31. b. 29.25 c. 5.85 d. 19.5 I want answer with solution as soon as possible Share with your friends Share 11 Geetha answered this Given that the solutions are isotonicπ1 = π2π = CRT = W2M2V × RTW2M2V × RTurea = W2M2V × RTNaCl1260 × 2 × RTurea = W258.5 × 10 × RTNaClSince gas constant R and T are equal 1260 × 2 urea = W258.5 × 10NaClW2 = 58.5 × 10 × 1260 × 2 = 58.5 g -10 View Full Answer Aditi Sharma answered this asd 1
