Dear Student , Here you have asked to find the potential difference , but we could not interpret between which two points Here the equivalent resistance between the points A and E is , RAE=2+3+5×6+42+3+5+6+4=10020=5 ΩSo the current flowing through the circuit is ,I=VR=105=2A Your question is not clear and appears to be incomplete Recheck your question and please be a little specific so that we can provide you with some meaningful help Looking forward to hear from you again! Regards

12b

Dear Student ,
Here you have asked to find the potential difference , but we could not interpret between which two points .
Here the equivalent resistance between the points A and E is ,

R_{A E} = \frac{(2 + 3 + 5) \times (6 + 4)}{(2 + 3 + 5) + (6 + 4)} = \frac{100}{20} = 5 Ω S o t h e c u r r e n t f l o w i n g t h r o u g h t h e c i r c u i t i s, I = \frac{V}{R} = \frac{10}{5} = 2 A

Your question is not clear and appears to be incomplete. Recheck your question and please be a little specific so that we can provide you with some meaningful help. Looking forward to hear from you again!
Regards

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