13.Q. The function f(x) = 2tan3x-3tan2x+12tanx +3, ∈ ( 0 , π 2 ) is, (A) increasing (B) decreasing (C) increasing in (0, π / 4 ) a n d d e c r e a sin g i n ( π / 4 , π / 2 ) (D) none of these Share with your friends Share 2 Aarushi Mishra answered this fx=2tan3x+3tan2x+12 tan x+3f'x=6 tan2x sec2x+6 tan x sec2x+12 sec2x=6sec2xtan2x+tan x+2Note: 6sec2x>0 and tan x>0 in x∈0, π2, therefore f'x>0 Hence fx is increasing 0 View Full Answer