19.A body of mass 2kg is at rest.A force of 4i+3j-5k N acts on it and displaces through 2i+j+2k m.The velocity acquired by the body is ---------

F  = 4i^+3j^-5k^S = 2i^+j^ +2k^work done = F.S =  4i^+3j^-5k^.2i^+j^ +2k^ = 8+3-10 = 1 joulethis work done is equal to the kinetic energy 1 = 12mv22m= v2v = 2m = 22v  = 1 m/s

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