19.A body of mass 2kg is at rest.A force of 4i+3j-5k N acts on it and displaces through 2i+j+2k m.The velocity acquired by the body is --------- Share with your friends Share 0 Neha Gupta answered this F ⇀ = 4i^+3j^-5k^S⇀ = 2i^+j^ +2k^work done = F⇀.S⇀ = 4i^+3j^-5k^.2i^+j^ +2k^ = 8+3-10 = 1 joulethis work done is equal to the kinetic energy 1 = 12mv22m= v2v = 2m = 22v = 1 m/s 0 View Full Answer