2.802 g of nitrogen is kept in a litre flask at 0 degree Celsius . Calculate the pressure exerted by the gas .

According to ideal gas equationpV= nRTpV= wM × RTIts given thatp= ?V= 1 Lw= 2.802 gMolecular mass of nitrogen M= 28 gR= Gas constant = 0.0821 L atm /K/molT= 0 0C =0 + 273 = 273 KSubstituting all these valuespV= wM × RTp= wRTMV     =2.802 × 0.0821 × 27328 × 1    = 2.243 atm

  • 24
What are you looking for?