2 cross roads , each of width 5 m , run at right angles through the centre of a rectangularpark - Maths - Perimeter and Area

Question

2 cross roads , each of width 5 m , run at right angles through
the centre of a rectangularpark of length 70 m and breadth 45 m and
parallel to its sides Find theareas of the roads Also find the cost
of constructing the roads at the rate of Rs 343 per sq m

Ankush Jain · Accepted Answer

Let ABCD be the rectangular park then EFGH and IJKL are the two
rectangular roads with width 5 m

â‡’ EH = MN = OP = FG = IL = MP = ON = JK
= 5 m

and AD = EF = HG = BC = 70 m

and AB = IJ = LK = DC = 45 m

Now area of roads = Area of EFGH + Area of IJKL - Area of MNOP

= (70 Ã— 5 + 45 Ã— 5 â€“
5 Ã— 5) m2

= (350 + 225 â€“ 25) m2

= 550 m2

Again, it is given that 
cost of constructing the roads = Rs 343 per
m2

Therefore, cost of constructing 550 m2

area of the roads = Rs 343 Ã— 550 = Rs
188650

2 cross roads , each of width 5 m , run at right angles through the centre of a rectangularpark of length 70 m and breadth 45 m and parallel to its sides.Find theareas of the roads. Also find the cost of constructing the roads at the rate of Rs 343 per sq. m.