2 positive charges 9nc and 4nc are placed at the points A and C respectively of a right angled triangle - Physics - Dual Nature Of Radiation And Matter

Question

2 positive charges 9nc and 4nc are placed at the points A and C
respectively of a right angled triangle ABC in which angle B
=90,AB=3cm and BC=2cm find the magnitude and direction of the
resultant electric field at B

Kulshekhar Mehta · Accepted Answer

<img alt="" src=
"https://img-nm%20mnimgs%20com/img/study_content/content_ck_images/images/charge(1)%20png">
Here Electric field due to charge at point A is
E1=kqara2 And electric field due to charge at point B is
E2=kqcrc2Now adding these fields vectorially we have
E=E12+E22+2E1E2cosθ here θ =90oE=E12+E22
Now we have qa= 9nc = 9×19-9 c, qc= 4nc
= 4×19-9 c, ra= AB= 3 cm = 0 03 m and
rc= CB= 2 cm = 0 02 m
k = 8 987 x 109 N
m2/C2
Putting all there value we have ,
E =k29×10-9(0 03)22+k24×10-9(0
02)22=k×10-910-8+10-8=8 987×2×10-4E=2×8
987×10-4N/c2And tanα =E1E2=qaqcrcra2=94232=1α =
45o where α is angle between resultant field and E2

2 positive charges 9nc and 4nc are placed at the points A and C respectively of a right angled triangle ABC in which angle B =90,AB=3cm and BC=2cm.find the magnitude and direction of the resultant electric field at B.