20 ml mixture of CH4 and CO2 when reacted with just sufficient oxygen,total volume after the complete reaction becomes 40 - Chemistry - States of Matter

Question

20 ml mixture of CH4 and CO2 when reacted with just sufficient
oxygen,total volume after the complete reaction becomes 40 ml at 1
atm and 500 K (for all volume measurments)% of CH4 by volume in the
initial mixture is
(A) 50% (B) 100% (C) 40% (D) 70%

Yasodharan · Accepted Answer

Dear Student,

The computation is as expressed below,

for reactant,n=PVRT=1×2010000 082×500=0
000487805 molafter reaction,n=1×4010000
082×500=0
00097561 mol% of methane = 0 0004878050
00097561×100%=50%Hence answer is Option (A) 50%

Regards

20 ml mixture of CH4 and CO2 when reacted with just sufficient oxygen,total volume after the complete reaction becomes 40 ml at 1 atm and 500 K (for all volume measurments)% of CH4 by volume in the initial mixture is (A) 50% (B) 100% (C) 40% (D) 70%

20 ml mixture of CH4 and CO2 when reacted with just sufficient oxygen,total volume after the complete reaction becomes 40 ml at 1 atm and 500 K (for all volume measurments)% of CH4 by volume in the initial mixture is
(A) 50% (B) 100% (C) 40% (D) 70%