21. In the adjoining figure, ABCD is a square of side 6cm. Find the area of the shaded region. (Ans: 34.428 sq cm) 22. In the adjoining figure, ABCD is a rectangle with sides 4cm and 8cm. Taking 8cm as the diameter, two semicircles are drawn. Find the area overlapped by the two semicircles.
(Ans:19.66 sq cm)
pls explain me
Here is the answer to your question (22).
For sector PQXR, PQ = QR = 4 cm
For the sector PYRQ, PR = PQ = 4 cm
In ∆PQR, PQ = QR = PR = 4 cm
∴ ∆PQR is an equilateral triangle of side 4 cm
∴ ∠PQR = ∠QPR = ∠PRQ = 60°
Now, area of the shaded portion
= 2area (PYRXQP)
= [area (sector PQXRMP) + area (segment PYMPR)]
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