23 .   I f   t h e   c a h r g e   o n   a n   e l e c t r o n   1 . 6 × 10 - 19   c o u l o m b s ,   h o w   m a n y   e l e c t r o n s   s h o u l d   p a s s   t h r o u g h   a   c o n d u c t o r   i n   1   s e c   t o   c o n s t i t u t e   1   a m p e r e   c u r r e n t ?  

Dear student,
1A=1C/s
No of electron =1/1.6*10^-19=6.25*10^18
Regards

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