25^ (n-1) + 100= 5^ 2n-1
25^ (n-1) + 100= 5^ 2n-1
given equation is:
let therefore the above equation becomes:
hence
since the base is same compairing the exponents:
25^ (n-1) + 100= 5^ 2n-1
25^ (n-1) + 100= 5^ 2n-1
given equation is:
let therefore the above equation becomes:
hence
since the base is same compairing the exponents: