3 vertices of a parallelogram taken in order are (1,2), (2, 4) and (3,7), then fourth vertex is ?
Use, Mid point of AC = mid point of BD
Let A = (1,2) , B = (2,4) , C = (3 , 7) and D = (x,y)
Now, mid point of AC = (2,9/2)
So, 2 + x/2 = 2 and 4 + y/2 = 9/2
Hence, x = 2 and y = 5
Hence (2,5) is the required point cheers...!!