36 identical chairs must be arranged in rows with the same no of chairs in each row. Each row must contain at least 3 chairs and there must be at least 3 rows. A row is parallel to the front of the room. How many different arrangements are possible?

Let the number of chairs = C
And, the number of rows = R
Since each row must have the same number of chairs. Therefore,
$C\times R=36 .....\left(1\right)$
Since each row must contain at least 3 chairs and there must be at least 3 rows. Therefore, C and R both are greater than or equal to 3.
Thus, the possible arrangements are $3\times 12, 4\times 9, 6\times 6, 9\times 4, 12\times 3$.
Hence, there are 5 different arrangements are possible.