3g of solute is dissolved in 30g of water to form of saturated solution at 298k. calculate the solubility of solute at this temprature.

The amount of the solute present in saturated solution at a particular temperature is called its solubility at that temperature. It is usually measured as the amount of solute present per 100 g of the solvent at a given temperature. We are given that 3g of solute is dissolved in 30g of water at 298 K to prepare a saturated solution. Thus

mass of solute present in 30g of water = 3g

mass of solute present in 1g of water = (3/30) g

mass of solute present in 100g of water = [(3 X 100) / 30] g = 10 g

Thus, the solubility of the solute at 298 K is 10 g per 100 g of water.