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4/5 of kg's apples were used on monday .the next day 1/3 of what was left was used. Weight in kg of apples left now is ?

$AppleusedonMonday=\frac{4}{5}kg\phantom{\rule{0ex}{0ex}}Remainingapple=1-\frac{4}{5}kg=\frac{1}{5}kg\phantom{\rule{0ex}{0ex}}Appleusednextday=\frac{1}{5}\times \frac{1}{3}kg=\frac{1}{15}kg\phantom{\rule{0ex}{0ex}}Appleusedboththedays=\frac{4}{5}+\frac{1}{15}=\frac{13}{15}kg\phantom{\rule{0ex}{0ex}}Remainingapple=1-\frac{13}{15}kg=\frac{2}{15}kg$

Regards

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