4 boys and 3 girls are standing in a line. Find the probability of boys and girls standing alternatively.
Please dont provide links. I asked this question earlier but a link was provided, which gave incomplete answer.

Dear student

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1/7th
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n(s)=> 4+3=7 [n(s) refferes to the empty/tolat sum]
n(E)= 1
P(E)=1/7

 
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boys 4/7 and girls 3/7
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