4nC2n : 2nCn = [1.3.5...(4n-1)] : [1.3.5...(2n-1)]^2

let us find the value of 2n!/n!

writing the odd terms and even terms seperately.

..............(1)

replacing n by 2n,

............(2)

now the given ratio can be written as:

now using (1) and (2):

which is the required result.

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