5.6 liters of methane gas is ignited in oxygen gas calculate the number of moles of carbon dioxide produced

The equation for the reaction:

CH ₄ + 2O₂ → CO₂ + 2H₂O

At S.T.P., 1 mol of gas = 22.4 L

So, 22.4 L of CH₄ will give 22.4L of CO₂ 
⇒ 1L of CH₄ will give 1L of CO₂ 
⇒ 5.6L of CH₄ gives 5.6L of CO₂

At S.T.P.

22.4L = 1 mol

⇒ 5.6 L = 5.6/22.4= 0.25 mol

Thus, 5.6L of methane will give 0.25 mol of carbon dioxide