5. Find the difference between area of the shaded part and unshaded part of the figure.

Dear student

Since GH=2cm and EF=8cmSO, ID=EF-GH=(8-2)cm=6cm   EFIDGHArea of DHI=Area of LMC=Area of MCR=Area of HQD=12×IH×ID=12×4×6=12cm2Area of JKPO=JK×KP=2×6=12cm2     KP=EF-PC=(8-2)cm=6cmArea of FGQE=Area of NABR=FG×EF=2×8=16cm2Area of shaded part=Area of DHI+Area of LMC+Area of JKPO=12+12+12cm2=36cm2Area of unshaded part=Area of MCR+Area of HQD+Area of FGQE+Area of NABR=12+12+16+16cm2=56cm2Difference between shaded part and unshaded part=Area of unshaded part-Area of shaded part=56-36cm2=20cm2


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38cm^2
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38^2cm
 
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Bro sahi h ya galat reply me
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Oh.. sorry 26 cm^2
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