5. Find the difference between area of the shaded part and unshaded part of the figure. Share with your friends Share 0 Lovina Kansal answered this Dear student Since GH=2cm and EF=8cmSO, ID=EF-GH=(8-2)cm=6cm ∵EF∥ID∥GHArea of △DHI=Area of △LMC=Area of △MCR=Area of △HQD=12×IH×ID=12×4×6=12cm2Area of JKPO=JK×KP=2×6=12cm2 ∵ KP=EF-PC=(8-2)cm=6cmArea of FGQE=Area of NABR=FG×EF=2×8=16cm2Area of shaded part=Area of △DHI+Area of △LMC+Area of JKPO=12+12+12cm2=36cm2Area of unshaded part=Area of △MCR+Area of △HQD+Area of FGQE+Area of NABR=12+12+16+16cm2=56cm2Difference between shaded part and unshaded part=Area of unshaded part-Area of shaded part=56-36cm2=20cm2 Regards 0 View Full Answer Gyan Kashyap answered this 38cm^2 1 Tora Sharma answered this 38^2cm 0 Gyan Kashyap answered this Bro sahi h ya galat reply me 0 Gyan Kashyap answered this Oh.. sorry 26 cm^2 0