5) In the circuit shown, cells are of equal emf E but of different internal resistance r 1 = 6 Ω   a n d   r 2 = 4 Ω . Reading of the ideal voltmeter connected across cell 1 is zero. Value of the external resistance R in ohm is equal to.



( A )     2 ( B )   2 . 4 ( C )   10 ( D )   24

Dear student
Applying kirchoffs loop rule in the given loop-2E+i×(r1+r2+R)=02E=i×(r1+r2+R)i=2E(r1+r2+R)..1As the voltage drop across the ideal voltmeter is zeroV+-V-=0E-i×r1=0i=Er1..2From eqn 1 and ..22E(r1+r2+R)=Er12r1=r1+r2+Rr1-r2=RR=6-4=2ΩRegards

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