53) In △ A B C , AC = BC, S is the circum - centre and ∠ A S B = 150 ° . F i n d ∠ C A B . ( a ) 55 1 2 ° ( b ) 52 1 2 ° ( c ) 62 1 2 ° ( d ) 35 1 2 ° Share with your friends Share 3 Varun Rawat answered this We know that angle subtended by an arc at the centre is double the angle subtended by the same arcat any point on the circle.Now, ∠ASB = 2∠ACB⇒150° = 2∠ACB⇒∠ACB = 75°In ∆ABC, CA = CB Given⇒∠CBA = ∠CAB Angles opposite to equal sides are equalIn ∆ABC,∠CBA + ∠CAB + ∠BCA = 180° Angle sum property⇒∠CAB + ∠CAB + 75° = 180°⇒∠CAB = 5212° 1 View Full Answer