5th question

Dear Student,

$$\begin{gathered} Given: \\ Probablity of atleast 1 HEAD is either HH or TH/HT \\ Favourable Outcomes for HH = 56 \\ Favourable Outcomes for HT/TH=110 \\ So \\ Favourable Outcomes for getting atleast 1 H=Favourable Outcomes for HH+Favourable Outcomes for HT/TH \\ =56+110 \\ = 166 \\ Total Outcome = 200 \\ Therefore probablity of at least one head = \frac{Favourable Outcomes}{Total Outcome} \\ =\frac{166}{200} \\ =\mathbf{ }\frac{\mathbf{41}}{\mathbf{50}}\mathbf{ }\mathit{A}\mathit{n}\mathit{s}\mathit{w}\mathit{e}\mathit{r} \end{gathered}$$


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