# 5y-y+1/3=6y+1/5

=> 4y + 1/3 = 6y + 1/5

=> 1/3 - 1/5 = 6y -4y

=> (5 - 3)/15 = 2y ( taking lcm)

=> 2/15 = 2y

=> y = 1/15

If the question is 5y - (y+1)/3 = 6y + 1/5

=>{ 15y - ( y + 1)}/3 = (30y + 1)/5 ( taking L.C.M)

=> (15y - y - 1)/3 = (30y + 1) /5

=> ( 14y - 1) * 5 = (30y + 1) * 3

=> 70y - 5 = 90y + 3

=> 20y = -8

=> y = -8/20

=> y = -2/5

Hope this helped you!

**
**