A 1 kg block is lifted vertically 1 m by a boy. The work done by the boy is

Here Work done is against to gravity
so; Work done=mgh
m = 1kg
g = 10 m/s2
h = 1m

w=mgh
=1*10*1
=10J

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If the force acts vertically then
work done = potential energy either mgh
where
m= 1kg
​g= 9.8m/s2
h = 1m
​so, mgh= 1 x 9.8 x 1
which is equal to
9.8Nm or 9.7J
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