A 15m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance *a. *Find the distance of the foot of the ladder from the wall*.*

Hi!

Here is the answer to your question.

The given situation can be represented as

Let the distance of the foot of the ladder from the wall be

*a*m. I.e., BC =*a*mApplying Pythagoras Theorem,

BC

^{2}+ AB^{2}= AC^{2}(Pythagoras Theorem)⇒

*a*^{2}+ (12)^{2}= (15 m)^{2}⇒

*a*^{2}= 225 – 144⇒

*a*^{2}= 81⇒

*a*= 9Thus, the distance of the foot of the ladder from the wall is 9 m.

Cheers!

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