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a 4m long rod of negligible weight is to be balanced about a point 125 cm from one end. A load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.
(a) a weight W is placed 250 cm from the support on the longer arm. find W.
(b) if W=5kgf, where must it be kept to balance the rod?
(c) to which class of lever does it belong?



since the the weight is balanced givenweight suspended at 60 cm =18 kgwe have to find the weight at 250 cm to balance the systemso 18×0.6m=w×2.5mw=18×0.62.5=4.32 kg(b)if 5 kg is placed then distance 18kg×0.6m=5kg×dd=18×0.65=2.16m or d =216 cmpart (c)  the lever belongs to cass 1 lever

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a- 18×0.6 = 2.5 × W
→ 4.32 kgf
b- 18× 0.6 =D×5
→2.16 m from support on longer arms
c- class I levers
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