A 50 litre solution of acid and water contains 10 litre of acid.
How much water must be added to make the solution 8% acidic.
volume of acid will remain same as it is not added.
let total volume of liquid formed after adding water be x then,
8% of x =10
x = (10 X100)/ 8
x = 125
hence total volume of solution = 125 , out of which 10 litre is acid
so water in the solution = 115 litre
water to be added = 115 - 50 = 65 litre
hope this helps....