A 60W light bulb has a current of 0.5 A passing through it. Calculate the no. of electrons passing a cross-section of the bulb and the no. of electron that pass that cross - section in one hour ? Share with your friends Share 4 Akansha Tyagi answered this i=net⇒n=ite=.5×60×601.6×10-19=1022electrons 3 View Full Answer