A and B are friends and their ages differ by 2 years. A's father D is twice as old as A and B is twice as old as his sister C. the age of D and C differ by 40 years. find the ages of A and B.
Let the ages of A = x years
and
age of B = y years.
Since, their ages differ by 2 years.
x - y =2 (Assuming A is older than B) -------------------(i)
Now, A's father D is twice as old as A,
Age of D = 2x years.
and
B's is twice as old as his C,
Age of C =
Also, the ages of D and C differ by 40 years.
∴On solving equations (i) and (ii) , we get,
Put the value of x in (i) we get
⇒ 26 - 2 = y
⇒ y = 24 years = B's age
∴Age of A is 26 years and B is 24 years.