a, b, c are positive integers forming an increasing geometric sequence, ba is a perfect square and log a +

log b + log c = 3. Find a + b + c.

Since a, b, c are in GP, b2=actaking log we get, 2logb=loga+logc......................1Now it is given loga+logb+logc=3...............2So from equation 1 and 2, 2logb=3-logb3logb=3logb=1So b =10Now using equation 2, logabc=3abc=103=100or ac=100So only possibility for inclreasing GP is 5×20So a=5, b=10, c=20So a+b+c=35

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