A bag contains Rs 187 in the form of 1 rupee, 50 paise, 10 paise coins in the ratio 3:4:5. Find the number of each type of coins?
{(3X1) + (4X0.50) + (5X0.10)} P =187
5.50 P = 187
P= 187/5.50=34
so 1 Rs coins =3X34=102 Rs.
50 Pase coins =4X34= 136 =68 Rs.
10 ps coins= 5X34=170=17 Rs.
5.50 P = 187
P= 187/5.50=34
so 1 Rs coins =3X34=102 Rs.
50 Pase coins =4X34= 136 =68 Rs.
10 ps coins= 5X34=170=17 Rs.