A bag of wheat weighs 50 kg, find the height to which it should be raised so that potential energy is 5000 J(g = 10m/s 2) ?

P.E = mgh

5000 = 50*10*h

5000 = 500h

h = 5000/500

h=10m

  • 6

ans is 10 m as its formula is mgh

so 5000=50*10*h

=500h

h=5000/500

h=10m

  • -2
h=10 m,
because 
P.E=mgh
5000=50*10*h
5000=500h
​h=5000/500
h=10m

 
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Mass of object (m)= 50kg (g)= 10 m/s Potential energy (P.E.)= 5000 J So, P.E.= mgh 5000 = 50×10×h 5000/500=h h= 10 m

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